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<small>Hi Chip,<br>
<br>
it is funny that your calculation about the photon has to a great
extend the same results as my general particle model if applied to
the electron. On the other hand your calculation regarding the
internal force in the photon assumes a very specific set up of a
photon and also a very specific way of its motion. So that you
have there a centrifugal force. This force is then by a factor of
1/</small><span style="mso-fareast-language:EN-US"><small>α </small></span><small>stronger
than the electric force. </small><span
style="mso-fareast-language:EN-US"><small>That is a numerical
result. Do you have at theory that has </small></span><span
style="mso-fareast-language:EN-US"><small><span
style="mso-fareast-language:EN-US">α</span> as an algebraic
result? <br>
<br>
My model has similar results, but in my understanding it has
less assumptions or preconditions. I do not use E = h*f as a
known fact but this relation follows from my model. And in my
case the force within the particle is h*c by comparison with the
QM-equation for the magnetic moment. So, if one builds the
relation between this force (h*c) and the electric force </small></span><span
style="mso-fareast-language:EN-US"><small><span
style="mso-fareast-language:EN-US">(Fe = e<sup>2</sup>/(4π ε<sub>0</sub>
r<sup>2</sup>)</span> then this relation is the definition of
</small></span><span style="mso-fareast-language:EN-US"><small><big><span
style="mso-fareast-language:EN-US"><small><span
style="mso-fareast-language:EN-US">α</span></small></span></big>,
not as a number but by algebra. <br>
<br>
So for me it follows from my model that </small></span><span
style="mso-fareast-language:EN-US"><small><big><span
style="mso-fareast-language:EN-US"><small><big><span
style="mso-fareast-language:EN-US"><small><span
style="mso-fareast-language:EN-US">α</span></small></span></big></small></span></big>
is the relation between the electrical and the strong force. To
what do you refer in order to avoid the impression that it is
only an accidental numerical result?<br>
<br>
Albrecht<br>
</small> </span><br>
<br>
<div class="moz-cite-prefix">Am 13.02.2016 um 19:13 schrieb Chip
Akins:<br>
</div>
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<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Hi
Albrecht<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">I
knew the relationship between the fine structure and the
strength of the Strong and EM forces for many years, but
only recently became aware of some of the implications.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">While
searching for causes for quantization of light and
quantization of mass (creating the fermionic particles we
observe), I found that the force required to cause the
photon to have a spin of ħ is equivalent in magnitude to the
Strong Force.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">The
math is simple:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">We
know the forward momentum of a photon is p=E/c. In order
for the photon to have a spin angular momentum of ħ and a
frequency of f=E/h we can calculate the photon’s effective
spin radius. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">First
we get the wavelength λ = c/f.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">We
can safely assume our photon model makes one revolution in
one wavelength (which gives the photon its frequency). So we
can also assume that the effective spin radius is the
wavelength divided by two times π or r = λ/2π.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">So
we have suggested a model for a photon which has a radius of
λ/2π and a forward momentum of E/c. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Let
us try out this model, and construct a gamma photon model
using the energy of the electron. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">The
energy of our photon is therefore 8.1871E-14 J. So its
frequency is f= E/h = 1.2356X10<sup>20</sup>Hz. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Which
yields a wavelength of λ = c/f = 2.4263X10<sup>-12</sup>m. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">That
makes the effective spin radius of this photon r = λ/2π =
3.8616X10-13m.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">The
forward momentum of this photon would then be p=
E/c=2.7309X10<sup>-22</sup>.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">And
the calculated spin angular momentum would be s = r p =
1.05457168X10<sup>-34</sup> = ħ.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">We
now have a spin ħ photon model which displays the known and
anticipated values for momentum and spin angular momentum
for such a photon.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">However
there is one piece of this photon model that we have not yet
addressed. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">That
is the force required to cause the energy of this photon to
spiral through space at the effective spin radius we have
suggested. <o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">In
order for energy traveling at c and with the momentum p
=2.7309X10<sup>-22 </sup>to circulate around a radius of r
= λ/2π = 3.8616X10-13m we would need a confinement force for
this energetic gamma photon of:<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Fc
= (p c)/r = 0.212014 Kg Force or 2.079147 Newtons Force.</span><!--[if gte msEquation 12]><m:oMath><span style='font-family:"Cambria Math",serif;mso-fareast-language:EN-US'><m:r><m:rPr><m:scr m:val="roman"/><m:sty m:val="p"/></m:rPr> </m:r></span></m:oMath><![endif]--><!--[if !msEquation]--><span
style="font-size:11.0pt;line-height:105%;font-family:"Calibri",sans-serif;color:black;position:relative;top:3.0pt;mso-text-raise:-3.0pt;mso-fareast-language:KO"><img
id="_x0000_i1025"
src="cid:part1.00010004.05070406@a-giese.de" height="18"
width="3"></span><!--[endif]--><span
style="mso-fareast-language:EN-US"><o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">The
calculated E field force at this radius is Fe = e<sup>2</sup>/(4π
ε<sub>0</sub> r<sup>2</sup>) = 0.0015472 Kg Force or
0.01517285 Newtons.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">And
Fe/Fc = α.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">So
it seems this force is present in everything subatomic and
particulate, from photons to all fermionic particles.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Chip<o:p></o:p></span></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US"><o:p> </o:p></span></p>
<div>
<div style="border:none;border-top:solid #E1E1E1
1.0pt;padding:3.0pt 0in 0in 0in">
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><b><span
style="color:windowtext;mso-fareast-language:EN-US">From:</span></b><span
style="color:windowtext;mso-fareast-language:EN-US">
General
[<a class="moz-txt-link-freetext" href="mailto:general-bounces+chipakins=gmail.com@lists.natureoflightandparticles.org">mailto:general-bounces+chipakins=gmail.com@lists.natureoflightandparticles.org</a>]
<b>On Behalf Of </b>Albrecht Giese<br>
<b>Sent:</b> Saturday, February 13, 2016 11:33 AM<br>
<b>To:</b> <a class="moz-txt-link-abbreviated" href="mailto:general@lists.natureoflightandparticles.org">general@lists.natureoflightandparticles.org</a><br>
<b>Subject:</b> Re: [General] Gravitational Waves and de
Broglie Waves<o:p></o:p></span></p>
</div>
</div>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal" style="margin-bottom:12.0pt">Hi Chip,<br>
<br>
I fully agree to your considerations and conclusions. It
follows (also) from my model that the fine structure constant
alpha shows the relation between the electric force and the
strong force. And the consequence is as well that the strong
force plays a much bigger role in the physical world than it
is assumed up to now.<br>
<br>
But are you aware that this is in strict conflict with main
stream physics? In traditional textbooks as well as at
Wikipedia it is said that alpha means the coupling between
electric charges. Also the original use of the constant,
introduced by Arnold Sommerfeld, was to explain fine
structures in atomic spectra. (The origin of the name.) But
recently I have also found a textbook with your explanations
(which is also mine.) <br>
<br>
How or where did you find this? I am wondering how long it
will take that main stream will accept this.<br>
<br>
Greetings<br>
Albrecht<br>
<br>
<span style="font-size:12.0pt;line-height:105%"><o:p></o:p></span></p>
<div>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt">Am
13.02.2016 um 16:39 schrieb Chip Akins:<o:p></o:p></p>
</div>
<blockquote style="margin-top:5.0pt;margin-bottom:5.0pt">
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Hi
All</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">An
issue has become interesting regarding the fine structure
constant.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">We
observe the fine structure constant in many different
ways. It is a prevailing constant which is uniquely and
widely manifest.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">It
is understood that the fine structure constant is simply
the difference in strength between the EM force (Fe) and
the Strong force (Fs). </span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Fs
= Fe α. And Fe = Fs/α. </span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">It
seems we may have overlooked the possibility that what we
call the nuclear strong force is present in many more
circumstances than we previously assumed.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">So
it seems that for every instance where we observe the fine
structure α, <b>both</b> of these forces must be at play,
or there must be a force equal to the strength of the
strong nuclear force, which we have not previously
recognized.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Thoughts?
Comments?</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US">Chip</span><o:p></o:p></p>
<p class="MsoNormal"><span style="mso-fareast-language:EN-US"> </span><o:p></o:p></p>
<div>
<div style="border:none;border-top:solid #E1E1E1
1.0pt;padding:3.0pt 0in 0in 0in">
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><b>From:</b>
General [<a moz-do-not-send="true"
href="mailto:general-bounces+chipakins=gmail.com@lists.natureoflightandparticles.org">mailto:general-bounces+chipakins=gmail.com@lists.natureoflightandparticles.org</a>]
<b>On Behalf Of </b>John Macken<br>
<b>Sent:</b> Friday, February 12, 2016 5:11 PM<br>
<b>To:</b> Nature of Light and Particles <a
moz-do-not-send="true"
href="mailto:general@lists.natureoflightandparticles.org"><a class="moz-txt-link-rfc2396E" href="mailto:general@lists.natureoflightandparticles.org"><general@lists.natureoflightandparticles.org></a></a><br>
<b>Subject:</b> [General] Gravitational Waves and de
Broglie Waves<o:p></o:p></p>
</div>
</div>
<p class="MsoNormal"> <o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">Hello Everyone, </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">It has been some time since I
have contributed to the discussion but I now have
something new to say because of the historic gravitational
wave announcement yesterday. It may seem as if
gravitational waves are far removed from particles, forces
and de Broglie waves, but in my world there is a strong
connection. There has been a lot of discussion in the
group about the properties of spacetime. However, the
discussion has largely ignored all the work done on
gravitational waves. These waves propagate in the medium
of spacetime and they reveal a lot of concrete information
about the properties of spacetime. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">Until yesterday there has been a
lot of doubt about whether the theoretically predicted
properties of gravitational waves were correct. Serious
efforts to detect gravitational waves have been
unsuccessful for over more than 25. We now know that the
problem was that the detectors were not sensitive enough
rather than a mistake in the concept or equations. A few
weeks after the sensitivity of LIGO was increased by a
factor of 3, they detected the first gravitational wave.
The first signal detected came from two black holes
merging about 1.3 billion years ago. The detected
pattern exactly matches the theoretical wave pattern
predicted for the merging of two black holes. The signal
was a strain wave in spacetime which had a frequency chirp
from about 30 Hz to about 250 Hz. The following link is
the first official technical paper on the subject (note
the hundreds of authors) : <a moz-do-not-send="true"
href="https://journals.aps.org/prl/pdf/10.1103/PhysRevLett.116.061102">https://journals.aps.org/prl/pdf/10.1103/PhysRevLett.116.061102</a></span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">The details about the emitted and
detected waves gives support to the model of the universe
that I have been proposing. I want to make several
points.</span><o:p></o:p></p>
<p class="MsoListParagraph"
style="text-indent:-.25in;mso-list:l0 level1 lfo2"><!--[if !supportLists]--><span
style="mso-list:Ignore">1)<span style="font:7.0pt
"Times New Roman""> </span></span><!--[endif]--><span
style="color:#444444">There is now no doubt that the
impedance of spacetime is Z<sub>s</sub> =<i> c</i><sup>3</sup>/<i>G</i>
= 4 x 10<sup>35</sup> kg/s. This comes from gravitational
wave equations. This impedance has been known to the
community of scientists working on gravitational waves for
a long time (references available). However, now all
physicists must admit that spacetime has this important
property. I claim that all the quantum mechanical wave
properties can be analyzed using the impedance of
spacetime. </span><o:p></o:p></p>
<p class="MsoListParagraph"
style="text-indent:-.25in;mso-list:l0 level1 lfo2"><!--[if !supportLists]--><span
style="mso-list:Ignore">2)<span style="font:7.0pt
"Times New Roman""> </span></span><!--[endif]--><span
style="color:#444444">This large impedance implies that
spacetime is not an empty void. This impedance is a
measurable property of spacetime that is about 28 orders
of magnitude larger than the impedance of steel. An empty
void would have no impedance. Also impedance implies an
elastic medium which has the ability to absorb energy and
return energy to a propagating wave. </span><o:p></o:p></p>
<p class="MsoListParagraph"
style="text-indent:-.25in;mso-list:l0 level1 lfo2"><!--[if !supportLists]--><span
style="mso-list:Ignore">3)<span style="font:7.0pt
"Times New Roman""> </span></span><!--[endif]--><span
style="color:#444444">The model of the vacuum that I have
proposed fits perfectly with this impedance. Quantum
mechanics implies that there is a Planck length
uncertainty in the distance between points and a Planck
time uncertainty in the time dimension. If this is
modeled as waves in spacetime which are continuously
modulating distance by Planck length and modulating the
rate of time by Planck time, then suddenly everything
fits. </span><o:p></o:p></p>
<p class="MsoListParagraph"
style="text-indent:-.25in;mso-list:l0 level1 lfo2"><!--[if !supportLists]--><span
style="mso-list:Ignore">4)<span style="font:7.0pt
"Times New Roman""> </span></span><!--[endif]--><span
style="color:#444444">Using gravitational wave equations
and the impedance of spacetime, it is possible to test the
hypothesis that spacetime is really filled with these
small amplitude waves. I have shown that zero point
energy exactly fits this model.</span><o:p></o:p></p>
<p class="MsoListParagraph"
style="text-indent:-.25in;mso-list:l0 level1 lfo2"><!--[if !supportLists]--><span
style="mso-list:Ignore">5)<span style="font:7.0pt
"Times New Roman""> </span></span><!--[endif]--><span
style="color:#444444">All the forces are explained not by
mysterious virtual photons and mysterious gravitons but by
waves and distortions of this “spacetime field”. </span><o:p></o:p></p>
<p class="MsoListParagraph"
style="text-indent:-.25in;mso-list:l0 level1 lfo2"><!--[if !supportLists]--><span
style="mso-list:Ignore">6)<span style="font:7.0pt
"Times New Roman""> </span></span><!--[endif]--><span
style="color:#444444">Using quantifiable properties of
spacetime and Planck length/time waves, it is possible to
move from hand waving models of particles, fields and de
Broglie waves to models which can be mathematically
analyzed and tested. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="color:#444444"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">Previously I was not clear enough
about whether these waves filling spacetime fit the
definition of being true “energy density”. Suppose that
we assume that the definition of “observable” energy is: <i>E</i><sup>2</sup>
= (<i>mc</i><sup>2</sup>)<sup>2</sup> + (<i>pc</i>)<sup>2</sup>.
All the fermions and bosons meet this definition of being
observable energy. I claim that the difference between
observable energy density (fermions and bosons) and the
unobservable energy density of the waves in spacetime is
that observable energy possess quantized angular momentum
(spin) while unobservable energy does not possess spin.
These Planck length/time waves have energy-like
properties such as a frequency, wave amplitude and
encounter the impedance of spacetime, but without
quantized angular momentum they do not interact with
fermions and bosons in a detectable way. These Planck
length/time waves are the most perfect superfluid
possible. Their presence is felt because they are
responsible for giving spacetime constants such as: <i>c</i>,
<i>G</i>, ħ, ε<sub>o</sub> and <i>Z</i><sub>s</sub>. Also
these small amplitude waves are responsible for
uncertainty and probabilistic characteristics of quantum
mechanics.</span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">If you treat these waves as if
they had quantized angular momentum (spin), then the
maximum energy density of spacetime would be about 10<sup>113</sup>
J/m<sup>3</sup>. However, without angular momentum to
make them quantized, the vacuum appears to be an empty
void which possesses mysterious physical properties. The
moment that new angular momentum is introduced into
spacetime, then some of the incomplete energy density of
the Planck length/time waves in spacetime becomes complete
and observable. For example, two spiraling black holes
introduce the missing angular momentum to some of the
waves in spacetime and they become observable
gravitational waves. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">I want to use information from
the above referenced gravitational wave paper to support
the contention that spacetime is filled with small
amplitude waves. According to this cited paper, the peak
power emitted by these black holes as they were merging
was 3.6 x 10<sup>49</sup> watts. This is a tremendous
power which approaches Planck power. It is possible to
drill deeper and analyze the forces involved in the
emission of this power. Energy is force times distance.
Power (P) is force (F) divided by speed (v). We know the
power emitted (3.6 x 10<sup>49</sup> watts) and the paper
gives the maximum speed as about ½ the speed of light.
Therefore the implied force retarding these two merging
black holes is about: </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">F = P/v = 3.6 x 10<sup>49</sup>
w/1.5 x 10<sup>8</sup> m/s = 2.4 x 10<sup>40</sup> N. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">Another calculation can be made
of the energy density of gravitational waves leaving the
surface of the black holes at the speed of light. This
calculation gives the emitted energy density propagating
through the spacetime near the Schwarzschild radius as
roughly 2 x 10<sup>29</sup> J/m<sup>3</sup>. This is more
than 10<sup>8</sup> times greater than the <i>E</i> = <i>mc</i><sup>2</sup>
energy density of osmium. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">An interpretation of Einstein’s
field equation is that there is a maximum possible force
which is: (1/8π)c<sup>4</sup>/G = 4.8 x 10<sup>42</sup>
N. Therefore the retarding force on the merging black
holes is about 2 orders of magnitude less than the maximum
possible force. The conservation of momentum says that
every force requires an equal and opposite reaction. What
is the opposite reaction in this case? It is easy to say
that momentum is being transferred to the emitted
gravitational waves, but then the question becomes: What
is physically happening in spacetime that allows space to
carry away this large a force and power? If spacetime is
visualized as an empty void, then the only explanation is
that the force is being transferred to gravitons. The
more widely accepted explanation of gravity is that
gravity is a geometrical effect and not a true force.
However this explanation is inadequate because geometry
cannot extract a power of 10<sup>49</sup> watts and a
force of 10<sup>48</sup> N. Even claiming that gravitons
exist and carry away the power is a problem. The paper is
also able to place a limit on the Compton wavelength of
gravitons (if they exist). The finding is that a graviton
must have a Compton wavelength greater than 10<sup>16</sup>
m which is a wavelength greater than 1 light year. This
obviously seems incompatible with the emission time and
frequency of the gravitational waves. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">If spacetime is filled with
Planck length/time waves which have an incomplete energy
density of about 10<sup>113</sup> J/m<sup>3</sup>, then it
is easy to see where the power and offsetting force comes
from. The gravitational waves are distorting the
tremendous incomplete energy density of the spacetime
field and making it complete by adding angular momentum.
This addition then completes the requirements for the
vacuum fluctuations to become observable energy density
which can transfer momentum and remove energy. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">What does all of this have to do
with particles, forces and de Broglie waves? Actually I
claim that all wave activity in quantum mechanics
ultimately is connected to the impedance of spacetime and
the Planck length/time waves that fill spacetime. I will
be writing a technical paper which explains this in more
detail and uses gravitational waves as numerical
examples. However, it is possible to find the answers if
you combine what has been said in this post with the
information in two attached papers. I suggest reading the
“foundation” paper first if you are interested. </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt">John M.</span><o:p></o:p></p>
<p class="MsoNormal"><span
style="font-size:12.0pt;line-height:105%;font-family:"Times
New Roman ,serif",serif"> </span><o:p></o:p></p>
<p class="MsoNormal"
style="margin-bottom:0in;margin-bottom:.0001pt;line-height:normal"><span
style="font-size:12.0pt;font-family:"Times New
Roman",serif;mso-fareast-language:EN-US"><br>
<br>
<br>
<o:p></o:p></span></p>
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