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<DIV><FONT color=#000080 size=2 face=Arial>Hi Chip,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Many thanks indeed for your succinct
and well-presented case ('succinct' is clearly a useful word in this discussion
- as well as a good strategy!).</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>I need to go through this carefully
and thoroughly and see how it relates to my own understanding of the
situation. As we're all agreed, we all have things to learn from each
other and (here I DO agree with Vivian's metaphor) each have some aspect of the
elephant (in the room?) to contribute. I'm really looking forward to
considering what you've said below and hopefully assimilating it into a fuller
understanding on my own part of the issues that need to be taken into
consideration.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>I'll come back to you when I've
processed it thoroughly (may take a few days) and have some thoughts to
offer.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Thanks again,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Grahame</FONT></DIV>
<BLOCKQUOTE
style="BORDER-LEFT: #000080 2px solid; PADDING-LEFT: 5px; PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black"><B>From:</B>
<A title=chipakins@gmail.com href="mailto:chipakins@gmail.com">Chip Akins</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=general@lists.natureoflightandparticles.org
href="mailto:general@lists.natureoflightandparticles.org">'Nature of Light and
Particles - General Discussion'</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Sunday, January 08, 2017 9:22
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [General] On particle
radius</DIV>
<DIV><BR></DIV>
<DIV class=WordSection1>
<P class=MsoNormal><SPAN style="COLOR: black" lang=EN-GB>Hi Dr Graham
Blackwell<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">I like the way you clearly and
succinctly write.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Let me explain some of the
reasons why I feel the radius of the electron decreases with
velocity.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">In order to accelerate the
electron at rest, we must apply energy (force through
distance).<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">The only way to apply energy to
the electron, when we get down to the basis, is to add energy to its existing
confined wave structure. Planck’s rule suggests that this confined wave
structure with energy added has a wavelength which is (h c)/E. If this is the
case and the momentum of this wave remains p=E/c, then in order to be a spin ½
hbar particle, it seems the electron must have a radius which is r = (h c)/(4
pi E). Where E is the new total energy with velocity throughout this
paragraph.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Then when we calculate the mass
of this particle from its confined momentum (as Richard has pointed out) we
get the expected relativistic (total) mass of the moving particle. m = E/(r w
c) = E/c^2= E Eo Uo. Which is exactly equivalent to m = y m. [where w = c/r
(angular frequency)].<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">This is the only scenario I have
found where all of the expected parameters are accommodated, and I have
searched extensively for other possibilities.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">We also note that the scattering
cross-section of an electron at relativistic velocities is very small, and
agrees with these assumptions quite well.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">In order for the electron radius
to remain the same size with velocity I think we have to ignore things which
seem quite important, and these specific things appear to be required in order
to tie several of the pieces of the puzzle together. It seems the picture is
just not complete unless the radius of the electron is reduced with
velocity.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Thoughts?<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Chip<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p><FONT color=#000080 size=2
face=Arial></FONT></o:p></SPAN></P></DIV></BLOCKQUOTE></BODY></HTML>