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</o:shapelayout></xml><![endif]--></head><body bgcolor=white lang=EN-US link=blue vlink=purple><div class=WordSection1><p class=MsoNormal><span style='color:black'>Hi All<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>For those of you who hold the hard line that nothing can move faster than c (a common interpretation of SR) the following is a bit of speculation.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>If the energy within the electron is all circulating at c, and the electron is an extended particle, then the field lines might look something like the following illustration…<o:p></o:p></span></p><p class=MsoNormal><!--[if gte vml 1]><v:shapetype id="_x0000_t75" coordsize="21600,21600" o:spt="75" o:preferrelative="t" path="m@4@5l@4@11@9@11@9@5xe" filled="f" stroked="f">
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</v:shape><![endif]--><![if !vml]><img width=175 height=166 src="cid:image002.png@01D26A71.4E3858D0" align=left hspace=12 v:shapes="Picture_x0020_1"><![endif]><span style='color:black'><o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>At any rate, the field lines would spiral outward from the center, moving at c at all points.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>This structure would not exhibit a specific frequency, or a finite set of frequencies, but would contain any frequency one might choose. So unless we can conceive of some mechanism which would only make certain frequencies visible, or some boundary conditions which would constrain the energy to a specific radius. Then this approach is not useful in discovering the electron’s mysteries.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>In fact, if a “photon”, or an EM wave if you prefer, can have a spin of hbar, and has a momentum of <i>p=E/c</i>, then the radius of action of this wave is <i>r = hbar/momentum</i>. Such a wave then must have a transverse displacement velocity of at least 3.489 times <i>c</i> in order for the wave to exist in this form. Also, the internal wavefront must be moving at the <i>sqrt(2) c. </i>So I think it must be that some things simply move faster than <i>c </i>as John Stewart Bell suggested. A more Lorentzian form of relativity.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>Chip<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><div><div style='border:none;border-top:solid #E1E1E1 1.0pt;padding:3.0pt 0in 0in 0in'><p class=MsoNormal><b><span style='font-size:11.0pt;font-family:"Calibri",sans-serif'>From:</span></b><span style='font-size:11.0pt;font-family:"Calibri",sans-serif'> General [mailto:general-bounces+chipakins=gmail.com@lists.natureoflightandparticles.org] <b>On Behalf Of </b>Dr Grahame Blackwell<br><b>Sent:</b> Sunday, January 08, 2017 4:10 PM<br><b>To:</b> Nature of Light and Particles - General Discussion <general@lists.natureoflightandparticles.org><br><b>Subject:</b> Re: [General] On particle radius<o:p></o:p></span></p></div></div><p class=MsoNormal><o:p> </o:p></p><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif;color:navy'>Hi Chip,</span><o:p></o:p></p></div><div><p class=MsoNormal> <o:p></o:p></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif;color:navy'>Many thanks indeed for your succinct and well-presented case ('succinct' is clearly a useful word in this discussion - as well as a good strategy!).</span><o:p></o:p></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif;color:navy'>I need to go through this carefully and thoroughly and see how it relates to my own understanding of the situation. As we're all agreed, we all have things to learn from each other and (here I DO agree with Vivian's metaphor) each have some aspect of the elephant (in the room?) to contribute. I'm really looking forward to considering what you've said below and hopefully assimilating it into a fuller understanding on my own part of the issues that need to be taken into consideration.</span><o:p></o:p></p></div><div><p class=MsoNormal> <o:p></o:p></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif;color:navy'>I'll come back to you when I've processed it thoroughly (may take a few days) and have some thoughts to offer.</span><o:p></o:p></p></div><div><p class=MsoNormal> <o:p></o:p></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif;color:navy'>Thanks again,</span><o:p></o:p></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif;color:navy'>Grahame</span><o:p></o:p></p></div><blockquote style='border:none;border-left:solid navy 1.5pt;padding:0in 0in 0in 4.0pt;margin-left:3.75pt;margin-top:5.0pt;margin-right:0in;margin-bottom:5.0pt'><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial",sans-serif'>----- Original Message ----- <o:p></o:p></span></p></div><div><p class=MsoNormal style='background:#E4E4E4'><b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'>From:</span></b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'> <a href="mailto:chipakins@gmail.com" title="chipakins@gmail.com">Chip Akins</a> <o:p></o:p></span></p></div><div><p class=MsoNormal><b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'>To:</span></b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'> <a href="mailto:general@lists.natureoflightandparticles.org" title="general@lists.natureoflightandparticles.org">'Nature of Light and Particles - General Discussion'</a> <o:p></o:p></span></p></div><div><p class=MsoNormal><b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'>Sent:</span></b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'> Sunday, January 08, 2017 9:22 PM<o:p></o:p></span></p></div><div><p class=MsoNormal><b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'>Subject:</span></b><span style='font-size:10.0pt;font-family:"Arial",sans-serif'> Re: [General] On particle radius<o:p></o:p></span></p></div><div><p class=MsoNormal><o:p> </o:p></p></div><p class=MsoNormal><span lang=EN-GB style='color:black'>Hi Dr Graham Blackwell<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>I like the way you clearly and succinctly write.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>Let me explain some of the reasons why I feel the radius of the electron decreases with velocity.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>In order to accelerate the electron at rest, we must apply energy (force through distance).<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'>The only way to apply energy to the electron, when we get down to the basis, is to add energy to its existing confined wave structure. Planck’s rule suggests that this confined wave structure with energy added has a wavelength which is (h c)/E. If this is the case and the momentum of this wave remains p=E/c, then in order to be a spin ½ hbar particle, it seems the electron must have a radius which is r = (h c)/(4 pi E). Where E is the new total energy with velocity throughout this paragraph.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>Then when we calculate the mass of this particle from its confined momentum (as Richard has pointed out) we get the expected relativistic (total) mass of the moving particle. m = E/(r w c) = E/c^2= E Eo Uo. Which is exactly equivalent to m = y m. [where w = c/r (angular frequency)].<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>This is the only scenario I have found where all of the expected parameters are accommodated, and I have searched extensively for other possibilities.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>We also note that the scattering cross-section of an electron at relativistic velocities is very small, and agrees with these assumptions quite well.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>In order for the electron radius to remain the same size with velocity I think we have to ignore things which seem quite important, and these specific things appear to be required in order to tie several of the pieces of the puzzle together. It seems the picture is just not complete unless the radius of the electron is reduced with velocity.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>Thoughts?<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>Chip<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p></blockquote></div></body></html>