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<DIV><FONT color=#000080 size=2 face=Arial>Chip et al.,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>With reference to your notes below on
particle radius and spin: theyre's more to say on the whole radius thing, which
I will hopefully add shortly, but I feel I should respond to your notes since I
said "a few days" almost a week ago.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>It's been noted by others and myself
before that a photon-formed electron will have spin (/ angular momentum) by
virtue of (a) the momentum of the photon acting cyclically, and (b) the angular
momentum of the photon itself. One apparent anomaly is that, as the speed
of the electron increases towards c, the formative photon becomes increasingly
linear, being fully linear at that limiting speed (which can of course only be
theoretical, a limiting state never reached); this creates the apparent anomaly
that, in the limit, the electron will have at least the full spin-1 of its
formative photon. Even at much lesser electron speeds the photon's own
spin component must be a consideration.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>The only possiblility by which this
could be nullified (since I think we're all agreed that a static electron will
have spin-1/2 just by virtue of the photon's linear momentum) is that the
formation of the electron must surely cancel out that photon spin component,
either by the cyclic motion of the photon acting in the opposite sense or by a
rotation (spinning motion), in the opposite sense, of the electron
itself. This has to be left for further thought (I have some thoughts on
it) - but it clearly doesn't add to the spin of the electron which, as
agreed, is 1/2 just from photon linear momentum.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Back to that momentum-induced spin:
the static electron has spin-1/2 due to photon linear momentum. As the
electron moves, progressively faster, the momentum of that photon increases due
to increasing electron speed (and so increasing photon frequency). BUT -
and this is the absolutely crucial point - the motion of that photon is now
helical, a combination of cyclic and linear. ONLY the cyclic component of
that photon momentum will contribute to electron spin (/ angular momentum) - the
linear component manifests as the linear momentum of the electron itself, gamma
m v (where m is rest-mass); that cyclic component is Eo/c - WHATEVER the speed
of the electron - this is quite apparent from the 'relativistic' energy-momentum
relation. In other words, in order to maintain that spin-1/2 for the
electron, the radius of the electron also has to be kept constant, as the cyclic
linear-momentum component of the formative photon is similarly constant.
If the radius of the electron is reduced then its angular momentum (/ spin) will
be reduced in direct proportion. This analysis totally supports the view
that electron diameter remains invariant (which is also supported by other
considerations - more on that later).</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>[In brief: to regard the full
increased momentum of the higher-frequency photon as contributing to electron
angular momentum is an over-simplification.]</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>As Albrecht and others have observed
in recent posts, experimental evidence interpreted as electron diameter is at
best an indication of cross-section of effective consequences; diameter inferred
from such experimental readings cannot be taken as a definitive statement of
particle size - there is clearly a lot of 'wiggle room' (literally!) in
this. The observations above on invariant electron spin would appear to be
rather more precisely definitive.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>With regard to the 'relativistic'
effective total mass of the moving particle, I'd wholly agree that this is gamma
m (where m is again rest-mass) - but we don't need to go via spin considerations
to get to that, it's implicit in the raised frequency of that formative photon,
in line with E = mc^2 {which again is not at all dependent on SR - but that's
another story].</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Best regards,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Grahame</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV style="FONT: 10pt arial">----- Original Message -----
<DIV style="BACKGROUND: #e4e4e4; font-color: black"><B>From:</B> <A
title=grahame@starweave.com href="mailto:grahame@starweave.com">Dr Grahame
Blackwell</A> </DIV>
<DIV><B>To:</B> <A title=general@lists.natureoflightandparticles.org
href="mailto:general@lists.natureoflightandparticles.org">Nature of Light and
Particles - General Discussion</A> </DIV>
<DIV><B>Sent:</B> Sunday, January 08, 2017 10:10 PM</DIV>
<DIV><B>Subject:</B> Re: [General] On particle radius</DIV></DIV>
<DIV><BR></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Hi Chip,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Many thanks indeed for your succinct
and well-presented case ('succinct' is clearly a useful word in this discussion
- as well as a good strategy!).</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>I need to go through this carefully
and thoroughly and see how it relates to my own understanding of the
situation. As we're all agreed, we all have things to learn from each
other and (here I DO agree with Vivian's metaphor) each have some aspect of the
elephant (in the room?) to contribute. I'm really looking forward to
considering what you've said below and hopefully assimilating it into a fuller
understanding on my own part of the issues that need to be taken into
consideration.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>I'll come back to you when I've
processed it thoroughly (may take a few days) and have some thoughts to
offer.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Thanks again,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Grahame</FONT></DIV>
<BLOCKQUOTE
style="BORDER-LEFT: #000080 2px solid; PADDING-LEFT: 5px; PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black"><B>From:</B>
<A title=chipakins@gmail.com href="mailto:chipakins@gmail.com">Chip Akins</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=general@lists.natureoflightandparticles.org
href="mailto:general@lists.natureoflightandparticles.org">'Nature of Light and
Particles - General Discussion'</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Sunday, January 08, 2017 9:22
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [General] On particle
radius</DIV>
<DIV><BR></DIV>
<DIV class=WordSection1>
<P class=MsoNormal><SPAN style="COLOR: black" lang=EN-GB>Hi Dr Graham
Blackwell<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">I like the way you clearly and
succinctly write.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Let me explain some of the
reasons why I feel the radius of the electron decreases with
velocity.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">In order to accelerate the
electron at rest, we must apply energy (force through
distance).<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">The only way to apply energy to
the electron, when we get down to the basis, is to add energy to its existing
confined wave structure. Planck’s rule suggests that this confined wave
structure with energy added has a wavelength which is (h c)/E. If this is the
case and the momentum of this wave remains p=E/c, then in order to be a spin ½
hbar particle, it seems the electron must have a radius which is r = (h c)/(4
pi E). Where E is the new total energy with velocity throughout this
paragraph.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Then when we calculate the mass
of this particle from its confined momentum (as Richard has pointed out) we
get the expected relativistic (total) mass of the moving particle. m = E/(r w
c) = E/c^2= E Eo Uo. Which is exactly equivalent to m = y m. [where w = c/r
(angular frequency)].<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">This is the only scenario I have
found where all of the expected parameters are accommodated, and I have
searched extensively for other possibilities.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">We also note that the scattering
cross-section of an electron at relativistic velocities is very small, and
agrees with these assumptions quite well.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">In order for the electron radius
to remain the same size with velocity I think we have to ignore things which
seem quite important, and these specific things appear to be required in order
to tie several of the pieces of the puzzle together. It seems the picture is
just not complete unless the radius of the electron is reduced with
velocity.<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Thoughts?<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p> </o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black">Chip<o:p></o:p></SPAN></P>
<P class=MsoNormal><SPAN style="COLOR: black"><o:p><FONT color=#000080 size=2
face=Arial></FONT></o:p></SPAN></P></DIV></BLOCKQUOTE>
<P>
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