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</o:shapelayout></xml><![endif]--></head><body lang=EN-US link=blue vlink=purple><div class=WordSection1><p class=MsoNormal><span style='color:black'>Hi Viv<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>After a bit of consideration…<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>It is not impossible to do a relatively good job of synchronizing the two clocks.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>The clocks are on spaceships, each equipped with a laser which generates a pulse, the pulse is generated 12 ns after receiving a pulse from the other ship. Once the first pulse is initiated, the ships continue to ping-pong pulses with their local 12ns delay for processing. We can then apply all the appropriate transformations to the ships, and the Doppler shift tells the relative velocity. The timing between pulses tells us the distance at the last round of signaling, so we can calculate the velocity and the distance between ships for any moment in their local time. Since we know how fast light travels, and how the Doppler shift relates to velocity, we can, in each ship, calculate a time to start counting clock ticks, and achieve principally the same results we would if the ships were collocated.<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>So, other than taking care to include all transformations, do you see a problem in synchronizing the clocks?<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:black'>Chip<o:p></o:p></span></p><p class=MsoNormal><span style='color:black'><o:p> </o:p></span></p><div><div style='border:none;border-top:solid #E1E1E1 1.0pt;padding:3.0pt 0in 0in 0in'><p class=MsoNormal><b><span style='font-size:11.0pt;font-family:"Calibri",sans-serif'>From:</span></b><span style='font-size:11.0pt;font-family:"Calibri",sans-serif'> Viv Robinson [mailto:viv@universephysics.com] <br><b>Sent:</b> Tuesday, August 22, 2017 4:56 PM<br><b>To:</b> Chip Akins <chipakins@gmail.com>; 'Nature of Light and Particles - General Discussion' <general@lists.natureoflightandparticles.org><br><b>Cc:</b> 'Darren Eggenschwiler' <darren@makemeafilm.com>; 'Innes Morrison' <innes.morrison@cocoon.life>; 'Mark, Martin van der' <martin.van.der.mark@philips.com><br><b>Subject:</b> RE: [General] STR twin Paradox<o:p></o:p></span></p></div></div><p class=MsoNormal><o:p> </o:p></p><div id="bloop_customfont"><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Hi Chip,<o:p></o:p></span></p></div><div id="bloop_customfont"><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'><o:p> </o:p></span></p></div><div id="bloop_customfont"><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Referring to your “<b>imagine</b>” section, highlighted in <b>bold</b> below. How do you synchronize clocks when you don’t know their velocity or how far apart they are? They can only communicate with each other by photons. You have two unknowns, speed and distance, and only one variable, redshift. They can be synchronized if they have a common reference point. That returns them to the common origin I mentioned below. <o:p></o:p></span></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'><o:p> </o:p></span></p></div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>So I restate my position. What is the physics by which the two clocks can be synchronized when their distance and velocities are unknown? That is obvious when they are synchronized at a common origin point or with respect to a common third party of known speed and distance from each. Then there is no paradox as I mentioned below. SRT and Doppler calculations will give the delay to the one that has moved the fastest with respect to the reference point when they next come close to each other. <o:p></o:p></span></p><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'><o:p> </o:p></span></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>You are correct in that all motion is relative in SRT. But there is no absolute reference point in space. CMB does not give such a reference. That reference point will always be relative to the common point about which the two clocks were synchronized. Without such a common point the two clocks can’t be synchronized. Without synchronization the results of the observation are questionable. <o:p></o:p></span></p></div><div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'><o:p> </o:p></span></p></div><div><div id="bloop_sign_1503435665430354176"><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Cheers,<o:p></o:p></span></p></div><div id="bloop_sign_1503435665430354176"><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'><o:p> </o:p></span></p></div><div id="bloop_sign_1503435665430354176"><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Vivian Robinson<o:p></o:p></span></p></div><p class=MsoNormal><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'><o:p> </o:p></span></p><p class=airmailon><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>On 23 August 2017 at 5:41:16 AM, Chip Akins (<a href="mailto:chipakins@gmail.com">chipakins@gmail.com</a>) wrote:<o:p></o:p></span></p><blockquote style='margin-top:5.0pt;margin-bottom:5.0pt'><div><div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>Hi Vivian</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'> </span>I would like to return to a discussion briefly which was ensuing a couple of months ago.<o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>Thank you for the careful explanation offered in the email below.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>However the point I was attempting to make a couple of months ago, deals only with the concept that all motion is relative in SRT. </span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'>So let us set up an experiment which excludes all effects of GRT, acceleration, gravity etc. and only evaluates this notion of SRT that all motion is relative.<o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>We have two identical clocks, moving relative to each other.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>For the sake of this experiment, <b>let us imagine that we have a means of synchronizing their clocks regardless of their separation. Or at least to start recording data at the same time, like when each reaches a predetermined distance from the other. (All Doppler effects accounted for.)</b></span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>An observer with clock A thinks clock B is moving.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>An observer with clock B thinks clock A is moving.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>After the “relative” motion has occurred for some time, the two clocks pass by in very close proximity to each other and exchange their data.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'> </span>The observer with clock A assumes the reading from Clock B will indicate that time has passed more slowly for B than for A. The observer with clock B assumes the reading from Clock A will indicate that time has passed more slowly for A than for B. Both cannot be correct.<o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>Clearly because of this, there IS A PARADOX, and that paradox is undeniably embedded in the notion that all motion is relative. Bringing in arguments from other theories, and proclaiming that there is no paradox <i>does not dismiss this logical problem inherent in SRT’s notion that all motion is relative</i>.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>If one clock is more stationary with regards to the CMB it is likely that is the one which will be more correct in their prediction of the clocks readings.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>They cannot both be correct. </span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>If they cannot both be correct, then all motion is NOT relative, but time is slowed for objects moving relative to space itself.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'>Chip</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='color:black'> </span><o:p></o:p></p><div><div style='border:none;border-top:solid #E1E1E1 1.0pt;padding:3.0pt 0in 0in 0in'><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><b><span style='font-size:11.0pt;font-family:"Calibri",sans-serif'>From:</span></b><span style='font-size:11.0pt;font-family:"Calibri",sans-serif'> Viv Robinson [<a href="mailto:viv@universephysics.com">mailto:viv@universephysics.com</a>] <br><b>Sent:</b> Wednesday, June 14, 2017 10:44 PM<br><b>To:</b> Chip Akins <<a href="mailto:chipakins@gmail.com">chipakins@gmail.com</a>>; Nature of Light and Particles - General Discussion <<a href="mailto:general@lists.natureoflightandparticles.org">general@lists.natureoflightandparticles.org</a>><br><b>Cc:</b> 'Darren Eggenschwiler' <<a href="mailto:darren@makemeafilm.com">darren@makemeafilm.com</a>>; 'Innes Morrison' <<a href="mailto:innes.morrison@cocoon.life">innes.morrison@cocoon.life</a>>; 'Mark, Martin van der' <<a href="mailto:martin.van.der.mark@philips.com">martin.van.der.mark@philips.com</a>><br><b>Subject:</b> Re: [General] STR twin Paradox</span><o:p></o:p></p></div></div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'> <o:p></o:p></p><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Hi All,</span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>The best way to sort out a problem is to understand the physics behind a situation and then use mathematics to calculate the magnitude of the physical effect attributed to it. Lets look at the so called "twin paradox".</span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Two observers O1 and O2 are next to and at rest with each other. Both have accurate atomic or whatever clocks. O2 is accelerated to speed v, travels for time t at v, is decelerated to rest wrt to O1, accelerated to v towards O1, again travels for a time and finally is decelerated to rest next to O1. They compare clocks. O2’s clock has slowed down wrt O1. Yet O2 has observed O1 traveling at v. So why doesn’t O1’s clock slow down wrt to O2?</span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>The answer is the acceleration. To accelerate O2, a force is applied to it. The combination of force and distance adds energy to O2 that is not added to O1. That energy is added to O2 in terms of kinetic energy or momentum change. No matter how small is the energy that is added, it is split between mass and velocity and causes a time dilation. They are the special relativity theory (SRT) corrections. That is something that O2 experiences and O1 does not experience.</span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>The fundamental difference that O2’s acceleration makes is that its mass increases as well as its velocity. Its time wrt O1 decreases. So while O2 may see O1 accelerating away, O1 is not the one experiencing the acceleration. Therefore O1 is not the observer whose mass is increasing and whose time is dilating. That is the physical reason why there is no "twin paradox". </span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Time dilation due to acceleration and deceleration (calculable from gravity equivalence) appears to be cumulative. Acceleration effects may make a difference if O2 is rapidly accelerated to v and then immediately rapidly decelerated to rest wrt O1, followed by a rapid acceleration to v and an immediate deceleration to rest next to O1. O2 will show SRT time dilation effect equal to the integrated effect of its relativistic velocity wrt O1. Those interested could calculate the acceleration effect from gravity equivalence and see how they compare.</span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Apart from that the time delay O2 experiences is because of the velocity multiplied by time effect. When the time traveled is much longer than the acceleration time, the time delay experienced by O2 will, for all practical purposes, be due to the SRT correction. </span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>The above has described the physics of the so called “twin paradox”. There is no paradox. O2’s time slows relative to O1 because O2 is the one that has been accelerated. Einstein was correct on both situations, the relativistic time correction and that they are only experienced by the accelerated observer. </span><o:p></o:p></p></div><div id="bloop_customfont"><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Of course you are free to disagree with the above. However if you feel compelled to point out that it is wrong, it is best done by forwarding the physics that makes it wrong and then present the mathematics required to show the magnitude of the physical effect. Then show how it agrees with experimental observation. In doing that remember that experimentalist using accurate atomic clocks have many times verified the SRT time corrections. </span><o:p></o:p></p></div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>There are two ways by which the SRT corrections can be applied. One is that there is an absolute zero reference somewhere in space and all corrections are applied from it. The other is that the SRT corrections are a property of any particle moving wrt another. I have previously published some calculations that suggest that the rotating or toroidal photon model for the structure of matter is responsible for the SRT corrections of matter. With all sub atomic particles, proton, neutron electron and neutrino having a rotating or toroidal photon structure, the SRT corrections are automatically inbuilt into every particle. As such I am happy that Einstein’s SRT corrections will always apply. </span><o:p></o:p></p></div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Remember that all linear motions are relative to the observer. However accelerations and circular motions are absolute. O1 and O2 may start out at 0.5 c wrt O3. O2 may be decelerated to rest wrt O3, remain at rest wrt O3 and then accelerated back to 0.5c to return to rest next to O1. O1 will still see O2’s clock as having lost time. O3 will see an entirely different situation. But remember O3 can only see what is happening to O1 and O2 by using photons. O3’s time dilation observations of O1 and O2 must include the SRT corrections as well as Doppler effect and distance changes. Complex but calculable to those interested.</span><o:p></o:p></p></div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Chip, regarding your analogy of A and B. At one stage in their life they were at the same place at the same time, even if it was only at birth. To find out which will be the younger you need to establish their background. If A remained at rest and B was accelerated away from A, B will be the younger when they both meet up again. If they both travelled away with equal accelerations, velocities and time they will both appear the same age. Both would be younger than a person born at the same place at the same time and remained at that place when they all met up again. </span><o:p></o:p></p></div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>I am quite happy to accept that all linear motion is relative. It agrees with SRT and experiment. I am also satisfied that the rotating or toroidal photon model for an electron (and other particles) gives a physical description that matches both SRT and observation. </span><o:p></o:p></p></div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Cheers,</span><o:p></o:p></p></div><div><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>Vivian Robinson</span><o:p></o:p></p></div><div><p class=airmailon0><span style='font-size:10.0pt;font-family:"Helvetica",sans-serif'>On 15 June 2017 at 12:43:26 AM, Chip Akins (<a href="mailto:chipakins@gmail.com">chipakins@gmail.com</a>) wrote:<o:p></o:p></span></p><div><blockquote style='margin-top:5.0pt;margin-bottom:5.0pt;font-variant-caps: normal;orphans: auto;text-align:start;widows: auto;-webkit-text-stroke-width: 0px;word-spacing:0px'><div><div><blockquote style='margin-top:5.0pt;margin-bottom:5.0pt'><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'>Hi John<span style='font-size:10.0pt'> </span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'>Yes. When I used the large circle example, I was afraid that someone would divert the conversation from Special Relativity. I suppose I deserve that.<span style='font-size:10.0pt'> </span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'>Back to Special Relativity.<o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'> <span style='font-size:10.0pt'>One Twin (Twin B) is moving at a constant highly relativistic velocity toward Twin A. Twin B thinks Twin A is moving, Twin A thinks Twin B is moving. When twin B arrives at Twin A’s location, Twin A expects Twin B to be younger, Twin B expects Twin A to be younger. Mutually exclusive conditions (if all motion is relative). So all motion is not relative. Simple, even for post grads, like you and me.</span><o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'>I welcome constructive, logical, suggestions, but please refrain from condescension, it does not help the cause.<o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'>Chip<o:p></o:p></p><p class=MsoNormal style='mso-margin-top-alt:auto;mso-margin-bottom-alt:auto'><o:p> </o:p></p></blockquote></div></div></blockquote></div></div></div></div></div></blockquote></div></div></body></html>