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    <p>Just another coment on your reply you said of the vertical
      Micelson Moreley Experiment "But I suspect, for the first one,
      that it is a property of his set up."</p>
    <p>So my point in sending it was to emphasize how easily we get
      fooled when we project properties of our experimental setup int
      onto the world.</p>
    <p>I just got a lead paper published in the August issue of the
      Journal of Consiousness studies ' entitled "The Rose tinted
      Glasses Effect" I'm quie proud of the accomplishment   First
      because the Journal of Consiousness Studies is THE journal in this
      field like getting published in Phys rev letters and second that
      tey were willing to take a physics paper shows we
      interdisciplinarians are making progress</p>
    <p>The point I tried to make was first made by Sir Author Eddington
      ' that its easy to get fooled by projecting properties of the
      measurement setup into the world' and since we do not take the
      human into account in physics but he is always part of the
      experimental setup we may very well be making some big mistakes.</p>
    <p> I hope my Vigier X paper gets published soon because there I try
      to show that it precisely the fact that Einstein did not account
      for the fact that his own imagination was always an aether
      background space that does have Em properties which transforms
      according to Lorenz equations. The speed of light is of course
      constant in each observers Now space , but since that observer is
      also in a gravitational potential the speed of light will be
      different in other observers Now spaces. A group of consensus
      observers will never see anything but the constancy of their own
      speed of light untill they look outside their own space. That is
      why M&M can not detect aether flow buit the CBR does.</p>
    <p>The proof however will be to find the explanation of the apearant
      increasing momentum of a particle in a cyclotron. So please help
      keeping me on target otherwise I will go into philosophy <br>
    </p>
    <p>best wishes</p>
    <p>Wolf<br>
    </p>
    <p><br>
    </p>
    <pre class="moz-signature" cols="72">Dr. Wolfgang Baer
Research Director
Nascent Systems Inc.
tel/fax 831-659-3120/0432
E-mail <a class="moz-txt-link-abbreviated" href="mailto:wolf@NascentInc.com">wolf@NascentInc.com</a></pre>
    <div class="moz-cite-prefix">On 8/23/2017 12:17 PM, Albrecht Giese
      wrote:<br>
    </div>
    <blockquote type="cite"
      cite="mid:381fc16c-bb70-5039-bbe9-b83d0d6d448a@a-giese.de">
      <meta http-equiv="Content-Type" content="text/html; charset=utf-8">
      <p>Wolf:</p>
      <p>Please stay at the topic we are just discussing here. We should
        first come to a result with those before extending our topics.<br>
      </p>
      <br>
      <div class="moz-cite-prefix">Am 21.08.2017 um 08:47 schrieb
        Wolfgang Baer:<br>
      </div>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <meta http-equiv="Content-Type" content="text/html;
          charset=utf-8">
        <p>Albrecht:</p>
        <p>I mentioned the Michelson Morley experiment because the URL I
          sent is an interesting alternative that gives a completely
          different answer which is probably wrong Watch  <a
            class="moz-txt-link-freetext"
            href="https://www.youtube.com/watch?v=aNEryiOKkrc"
            moz-do-not-send="true">https://www.youtube.com/watch?v=aNEryiOKkrc</a></p>
      </blockquote>
      Yes, I have seen both videos. But I suspect, for the first one,
      that it is a property of his set up. If in the upright position
      the elements of the apparatus move only by a micrometer by
      gravity, then this effect is already understandable. Generally
      speaking, the author did not present an error investigation; and
      that is essential for every experiment.<br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <p>However in general this experiment is extremely pertinent
          because the inability to detect ether drift is one of the main
          pillars of Einstein's approach and one of the main pillars of
          my consciousness theory of why why we should not detect the
          background space which is attached and generated by us. I am
          working on my book fro ROutledge Press and would be happy to
          start sending you parts of it for comments on this observer
          oriented event theory. <br>
        </p>
      </blockquote>
      But my question was about the measurement of the speed of light c.
      We should not jump but bring one question to an end before
      switching to philosophy or similar. <br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <p> </p>
        <p>You are very right I should learn more about synchrotrons but
          we re not discussing the standard text book approach and its
          assumptions so I am hoping you will meet me half way and tell
          my specifically why you think I'm wrong instead of generally
          asking me to go look at a text book and hoping I would guess
          your objection. <br>
        </p>
      </blockquote>
      In the following you see the accelerating pieces of a <i>linear </i>accelerator.
      This is showing how the speed of a particle - like an electron -
      determines the switching frequency<br>
      <br>
                <img id="uid_0"
        src="cid:part2.3424F32F.865C3132@nascentinc.com"
        data-deferred="1" class="_WCg"
        title="https://de.wikipedia.org/wiki/Linearbeschleuniger"
        alt="Bildergebnis für linearbeschleuniger" height="301"
        width="408"><br>
      In a synchrotron this is built in a circular way. <br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <p> </p>
        <p>Now you've started to be mores specific and I greatly
          appreciate that. The definition of momentum is <span
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                                        style="display: inline-block;
                                        width: 0px; height: 4.012em;"></span></span><span
                                      style="position: absolute; clip:
                                      rect(2.677em, 1001.02em, 4.848em,
                                      -1000em); top: -4.014em; left:
                                      0em;"><span style="font-family:
                                        MathJax_Size2;">√</span><span
                                        style="display: inline-block;
                                        width: 0px; height: 4.012em;"></span></span></span></span><span
                                  style="display: inline-block; width:
                                  0px; height: 4.012em;"></span></span><span
                                style="position: absolute; clip:
                                rect(0.787em, 1003.87em, 1.235em,
                                -1000em); top: -1.269em; left: 0em;"><span
                                  style="display: inline-block;
                                  overflow: hidden; vertical-align: 0em;
                                  border-top: 1.3px solid; width:
                                  3.873em; height: 0px;"></span><span
                                  style="display: inline-block; width:
                                  0px; height: 1.049em;"></span></span></span></span></span></span></span><span
                      style="display: inline-block; width: 0px; height:
                      2.16em;"></span></span></span><span
                  style="display: inline-block; overflow: hidden;
                  vertical-align: -2.005em; border-left: 0px solid;
                  width: 0px; height: 3.774em;"></span></span></nobr></span></p>
        <p><span class="_Tgc _y9e">However the derivation of this
            equation is not at all straight forward since we are talking
            about three dimensions and the formula is different in the
            direction of motion vs the cross direction terms. In the
            circular orbit we are talking about a momentum in te radial
            direction vs one in the angular direction and furthermore
            the particle is in an accelerated frame. <br>
          </span></p>
      </blockquote>
      The point is here that the momentum of the electron increases
      permanently, but the speed is limited to c. And as there is p =
      m*v , and at the end v = c, how can you explain the increase of p
      if assuming m to be constant? <br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <p><span class="_Tgc _y9e"> </span></p>
        You are saying particles are accelerated to near the speed of
        light and easily measured, yes but this is a one way near speed
        of light measurement and one needs to examine  this carefully.<span
          class="_Tgc _y9e">I've read in numerous places that the Large
          Hadron Collider is capable of accelerating protons at
          0.999999991 c,- At those speeds the circumference of "C" is
          the stationary distance and the time is the time statinary
          period tp measured at one point whenever the particle comes
          around. so its velocity is C/tp, However the particle is  
          stationary in its own reference frame and only feels a radial
          gravitational pull outward for which the factor under the
          integral depends upon the log of the radius</span><br>
      </blockquote>
      When we say that an object has a certain speed we mean the speed
      measured in our laboratory frame. For other frames (also the one
      of the particle itself) it has to be determined by the Lorentz
      transformation. But that is a different story than what we are
      discussing here. <br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <br>
        Furthermore we must talk about the momentum of a charged
        particle since presumably the momentum is measured by the
        curvature on a charge induced by a magnetic field.<br>
      </blockquote>
      That is one way. The other - which relates to the energy of a
      particle - is its conversion into other particles. So, an electron
      and a positron accelerated in a storage ring can collide and in
      this moment be converted into particles of a much higher mass (a
      mass of more than 1000 times the mass of the electron). How is
      this possible if the electron does not change its mass (and the
      positron as well)?<br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <br>
        This it gets very complex and your recommendation to understand
        more is appropriate. However is the situation not similar to the
        central force problem of a particle moving in an atom where the
        gravitational and electric forces are balanced <br>
      </blockquote>
      The gravitational force is completely irrelevant for the processes
      in an atom. I have many times given you numbers that for such
      influence the gravitational force is too low by more than 30
      orders of magnitude. - Why do I write this again and again, and
      you never react on it but repeat completely wrong numbers or
      assumption again and again?? So we cannot go on.<br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <br>
        i will try to get you a calculation which shows that for an atom
        the assumption that charge and mass are at a point is no longer
        valid and in fact the two are separated. Thus the momentum of a
        particle is dependent upon the separation distance. this allows
        me to calculate the momentum and energy of a particle from
        contant mass and force since the correction factors are used to
        explain an internal geometry to matter rather than a change in
        the value of mass.<br>
      </blockquote>
      So a particle without a charge does not have any momentum?<br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <br>
        please stand by<br>
        <br>
        Wolf<br>
      </blockquote>
      <br>
      Please treat the questions we are discussing right now here. The
      rest please later. <br>
      <br>
      Albrecht<br>
      <blockquote type="cite"
        cite="mid:59a8f7ad-b977-3b0a-6345-00e2ea691346@nascentinc.com">
        <br>
        <pre class="moz-signature" cols="72">Dr. Wolfgang Baer
Research Director
Nascent Systems Inc.
tel/fax 831-659-3120/0432
E-mail <a class="moz-txt-link-abbreviated" href="mailto:wolf@NascentInc.com" moz-do-not-send="true">wolf@NascentInc.com</a></pre>
        <div class="moz-cite-prefix">On 8/18/2017 8:18 AM, Albrecht
          Giese wrote:<br>
        </div>
        <blockquote type="cite"
          cite="mid:320ecd97-0387-c8ab-1de5-66e497cbdfae@a-giese.de">
          <meta http-equiv="Content-Type" content="text/html;
            charset=utf-8">
          <p>Wolf,</p>
          <p>why do you mention the Michelson Morley experiment? It was
            not the purpose of  it to determine the speed of light. And
            it is in no way suitable to do this determination. It was
            designed to measure the ether drift. <br>
          </p>
          <p>A particle accelerator is, on the other hand, a very good
            way to determine the behaviour of c. Because when the
            particle flies along the chain of acceleration sections, the
            fields of these sections have to be switched in a properly
            synchronized way so that an acceleration can happen.
            Therefore the speed of the particle is very simple logic. At
            which point do you doubt this process?</p>
          <p>If it is now visible that this speed has an upper bound
            (more is not necessary), but the momentum of the particle
            increases permanently, then the increase of mass is the only
            explanation. Or do you have another one? - The increase of
            momentum is easily measured in a magnetic field.</p>
          <p>From these facts together the increase of mass has to be
            concluded. I do not know any other explanation. Do you have
            one?</p>
          <p>Your doubt of this is in my view a consequence of the fact
            that you have never looked into the design of a synchrotron.
            You should do that urgently before presenting unchained
            statements about relativistic facts. <br>
          </p>
          <p>Albrecht<br>
          </p>
          <br>
          <div class="moz-cite-prefix">Am 17.08.2017 um 08:16 schrieb
            Wolfgang Baer:<br>
          </div>
          <blockquote type="cite"
            cite="mid:ddc8528c-fc3f-9bd8-3920-4ec33bba8607@nascentinc.com">
            <meta http-equiv="Content-Type" content="text/html;
              charset=utf-8">
            <p>wel the first thin I would like to see is nano second
              pulses reproducing a michelson Morely type experiment <br>
            </p>
            <p>But the simplest thing is to look at the theory of the
              synchroton design you keep talking about  are you talking
              about the energy formula</p>
            <p> m*c<sup>2</sup> = m<sub>0</sub>*c<sup>2</sup> *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>)<font
                size="-1"> </font> that we both agree on. If so then we
              are only in disagreement about the interpretation and the
              assmptions inside tha<font size="-1">t i</font>nterpretation<font
                size="-1">, observations like this E-mail in front of
                your nose are facts I do not dispute facts, I'm
                interested in <br>
              </font></p>
            <p><br>
            </p>
            <p>by the way have you seen <br>
            </p>
            <div class="" style="font-family: TimesNewRomanPSMT;"><br
                class="">
            </div>
            <div class="" style="font-family: TimesNewRomanPSMT;"><font
                class="" face="TimesNewRomanPSMT"><a
                  href="https://www.youtube.com/watch?v=7T0d7o8X2-E"
                  class="" moz-do-not-send="true">https://www.youtube.com/watch?v=7T0d7o8X2-E</a><br>
                <br>
                The truth is hard to come by.<br>
                <br>
                Wolf<br>
                <br>
              </font></div>
            <pre class="moz-signature" cols="72">Dr. Wolfgang Baer
Research Director
Nascent Systems Inc.
tel/fax 831-659-3120/0432
E-mail <a class="moz-txt-link-abbreviated" href="mailto:wolf@NascentInc.com" moz-do-not-send="true">wolf@NascentInc.com</a></pre>
            <div class="moz-cite-prefix">On 8/16/2017 7:42 AM, Albrecht
              Giese wrote:<br>
            </div>
            <blockquote type="cite"
              cite="mid:0dc5ad30-70e6-f9e5-256c-8f1ae27ed3e1@a-giese.de">
              <meta http-equiv="Content-Type" content="text/html;
                charset=utf-8">
              <p>So, what is <i>your </i>way to measure the speed of
                light so that you trust the result?<br>
              </p>
              <br>
              <div class="moz-cite-prefix">Am 16.08.2017 um 07:56
                schrieb Wolfgang Baer:<br>
              </div>
              <blockquote type="cite"
                cite="mid:24371479-20f6-67e1-a010-f1bc44e5dd89@nascentinc.com">
                <meta http-equiv="Content-Type" content="text/html;
                  charset=utf-8">
                <p>You still do not grasp the idea that theory and
                  therefore the assumption of theory determine the
                  interpretation and therfore what we thing we are
                  seeing.<br>
                </p>
                <pre class="moz-signature" cols="72">Dr. Wolfgang Baer
Research Director
Nascent Systems Inc.
tel/fax 831-659-3120/0432
E-mail <a class="moz-txt-link-abbreviated" href="mailto:wolf@NascentInc.com" moz-do-not-send="true">wolf@NascentInc.com</a></pre>
                <div class="moz-cite-prefix">On 8/15/2017 12:44 PM,
                  Albrecht Giese wrote:<br>
                </div>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <meta http-equiv="Content-Type" content="text/html;
                    charset=utf-8">
                  <p>Wolf: <br>
                  </p>
                  <p>it may be good to have new ideas or new insights,
                    but please do not offer equations which are in clear
                    conflict to safe experiments. <br>
                  </p>
                  <br>
                  <div class="moz-cite-prefix">Am 15.08.2017 um 07:45
                    schrieb Wolfgang Baer:<br>
                  </div>
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <meta http-equiv="Content-Type" content="text/html;
                      charset=utf-8">
                    <p>Albrecht:</p>
                    <p>You said "Your equation   Your equation   m*c<sup>2</sup>
                      = m<sub>0</sub>*c<sup>2</sup> *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>)<font
                        size="-1">   </font>is correct. It describes
                      the increase of mass at motion.  But your
                      equation <font size="+1"> </font>c<sup>2</sup> =
                      c<sub>0</sub><sup>2</sup> *(1/(1-v<sup>2</sup>/c<sub>0</sub><sup>2</sup>)<sup>1/2</sup>)  
                      does not have any meaning for me. And I do not
                      understand how you have deduced it. I have asked
                      you the other day what this equation means in your
                      view, but you did not answer this.' <br>
                    </p>
                    <p>I thought I had answered many times. Lets assume
                      we both agree on this equation m*c<sup>2</sup> = m<sub>0</sub>*c<sup>2</sup>
                      *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>)
                      is correct.</p>
                    <p>Now how do you interpret it?</p>
                    <p>If you believe in Einsteins postulate that c is
                      constant then you can logically divide c oyt of
                      the equation and get m = m<sub>0</sub>*(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>)
                      which you believe has been proven in accelerator
                      designs.</p>
                    <p>I on the other hand recognize that Einstein's
                      postulate is precisely a postulate, an initial
                      assumption that may or may not be correct.</p>
                    <p>We are both and all of us in this discussion
                      group exploring the validity of initial
                      assumptions. Therefor Allow me to assume Eistein's
                      assumption is one way of developing a theory but
                      not the only way. If we assume mass is the
                      invariant instead of the speed of light then the
                      very same equation we both agree on could be
                      written as m*c<sup>2</sup> = m*c<sub>0</sub><sup>2</sup>
                      *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>).
                      Now we can cancel the "m' and get c<sup>2</sup> =
                      c<sub>0</sub><sup>2</sup> *(1/(1-v<sup>2</sup>/c<sub>0</sub><sup>2</sup>)<sup>1/2</sup>)  
                      <br>
                    </p>
                  </blockquote>
                  The operation of accelerators show every day and every
                  second that the speed of particles has a limit at the
                  speed of light c. And as on the other hand the energy
                  (or momentum) of a particle in an accelerator is
                  increased to above any limit, the mass of that
                  particles must increase. There is no other
                  explanation, or do you have one?<br>
                </blockquote>
                The operation of acceloators show m*c<sup>2</sup> = m<sub>0</sub>*c<sup>2</sup>
                *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>)<font
                  size="-1">  which can be interpreted in two ways. I
                  challenge you again to show me why your interpretation
                  of c remaining contant and m needs to increase is the
                  right one?<br>
                </font>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p> </p>
                    <p>This may not have any meaning to you, but it that
                      is the case you do not understand how a community
                      of scientists could be so brain washed that they
                      accept an assumption for gospel truth and do not
                      want to understand circular reasoning which will
                      always prove the initial assumption is true.</p>
                  </blockquote>
                  Why do you not explain a physical process which is
                  described by your equation above: "c<sup>2</sup> = c<sub>0</sub><sup>2</sup>
                  *(1/(1-v<sup>2</sup>/c<sub>0</sub><sup>2</sup>)<sup>1/2</sup>)" 
                  ?<br>
                </blockquote>
                I've explained this many times the speed of EM process
                in a particle or coordinate frame built of particle is
                dependent upon the total energy potential the particle
                experiences gravitational potentialis one of the
                components the particle is in. The speed of light and
                all processes including clock rates slow down when the
                clock is in a lower gravity potential<br>
                mc<sup>2 </sup>=~  m c<sub>0</sub><sup>2</sup> + 1/2 mv<sup>2</sup>
                  
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p>Now i know you are smart enough to understand
                      this choice of initial assumptions.</p>
                  </blockquote>
                  Which initial assumptions do you mean?<br>
                </blockquote>
                That the speed of light is constant. instead of being
                dependent on the energy potential it is in.<br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p>An further more if we rewrite the equation we
                      both agree on as    m*c<sup>2</sup> = m<sub>0</sub><sup>3/2</sup>*c<sup>3</sup>
                      *(1/(mc<sup>2</sup>-mv<sup>2</sup>)<sup>1/2</sup>)we
                      would recognize the mc<sup>2</sup>-mv<sup>2</sup>
                      in the corrective factor as the negative classic
                      Lagrangian when the potential energy of the a mass
                      inside a universe mass shell is 1/2 mc<sup>2</sup>.
                      This means mc<sup>2</sup> is the escape energy to
                      get outside our Universe of mass surrounding us.
                      In other words we live in a flat space at the
                      center od a ball of mass. Simple and consistent
                      with intuition. <br>
                    </p>
                  </blockquote>
                  This again assumes that the mass of an object is
                  constant if put to motion. This is clearly falsified
                  by safe experiments.<br>
                </blockquote>
                You keep saying clearly falsified but you do not show me
                the safe experiments I believe the experiments you refer
                to are based on this equation m*c<sup>2</sup> = m<sub>0</sub>*c<sup>2</sup>
                *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>) and I
                keep saying it can be interpreted in two ways <br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p> </p>
                    <p>Now I ask you to show me experiments that cannot
                      be explained with the assumptions leading to c<sup>2</sup>
                      = c<sub>0</sub><sup>2</sup> *(1/(1-v<sup>2</sup>/c<sub>0</sub><sup>2</sup>)<sup>1/2</sup>) 
                      <br>
                    </p>
                  </blockquote>
                  My question again - not answered by you - is: which
                  physical process is described by this equation in your
                  view? For me it is just a collection of symbols
                  without any message.<br>
                </blockquote>
                Ive again told you the physical process is to include
                the gravity potential of the distant stars Machs
                principle<br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p> </p>
                    <p>since I or we have shown you arguments that
                      Einsteins assumption is inconsistent with</p>
                    <p>1) gravity must be infinite or there would be a
                      tangential component to increase our orbit</p>
                  </blockquote>
                  Which gravity, i.e. the gravity of which object is
                  infinite in your view?<br>
                </blockquote>
                I meant the speed of gravity, this is also a problem
                with your rotating charges unless the interaction speed
                is infinite a tangential component will arise which
                makes the orbit unstable <br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p>2) the perihelion correction is based upon the
                      calculation classic i.e. infinite speed of gravity
                      calculations</p>
                  </blockquote>
                  To my understanding the perihelion shift is caused by
                  the fact that the planet changes its mass during the
                  orbit because the speed changes.<br>
                </blockquote>
                That again is an interpretation but the prehelion shift
                is calculated by assuming Newtons infinite gravity it
                again is false reasoning. You can explain the shift by
                making new assumptions, but if you apply those
                assumptions consistently you get a different answer to
                the shift and one that is inconsistent wih Einsteins
                calculations. We sent out the paper on this i can dig it
                up and send itr again.<br>
                <br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p>3) Shapiro's speed of light calculation</p>
                  </blockquote>
                  Shapiro's result for the speed of light is in full
                  agreement with Einstein and also in full agreement
                  with my approach to gravity.<br>
                </blockquote>
                it proves the speed of light is dependent u[pon the
                gravito-inertial  field the light is in and is not
                constant. So why are you so critical of my c<sup>2</sup>
                = c<sub>0</sub><sup>2</sup> *(1/(1-v<sup>2</sup>/c<sub>0</sub><sup>2</sup>)<sup>1/2</sup>) 
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p>4) Gravitational shielding during eclipses and
                      anomalies in satellite orbits (not sure about this
                      one) <br>
                    </p>
                  </blockquote>
                  Where was gravitational shielding observed? And which
                  anomalies in satellite orbits do you mean?<br>
                </blockquote>
                I cannot remember right now but maybe Candra sent some
                paper that mentioned the anomalies and gravity effects
                measured during an eclipse<br>
                perhaps someone will remember the reference. <br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <p> </p>
                    <br>
                    Einstein should have listened to Mach.<br>
                  </blockquote>
                  If Einstein would have listened to Mach he would have
                  accepted the existence of a fixed frame of reference
                  (this kind of an ether). I assume the same as Mach.<br>
                </blockquote>
                The why are you so critical? My on;y contribution is to
                realize that the fixed frame of reference is the
                perceptive space attached to each observer<br>
                you must understand yourself in the picture or you have
                only half the truth.<br>
                 <br>
                <blockquote type="cite"
                  cite="mid:340c668f-8163-c981-8561-c895ea8bb980@a-giese.de">
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <br>
                    <br>
                    Best wishes ,<br>
                    Wolf<br>
                    <pre class="moz-signature" cols="72">Dr. Wolfgang Baer
Research Director
Nascent Systems Inc.
tel/fax 831-659-3120/0432
E-mail <a class="moz-txt-link-abbreviated" href="mailto:wolf@NascentInc.com" moz-do-not-send="true">wolf@NascentInc.com</a></pre>
                  </blockquote>
                  Best wishes back<br>
                  Albrecht<br>
                  <br>
                  <blockquote type="cite"
                    cite="mid:7a82bab5-1de6-d724-6d10-5efc345348f8@nascentinc.com">
                    <div class="moz-cite-prefix">On 8/11/2017 4:24 AM,
                      Albrecht Giese wrote:<br>
                    </div>
                    <blockquote type="cite"
                      cite="mid:f4248e86-0d35-7b10-d248-1876fcb99f4b@a-giese.de">Your
                      equation   m*c<sup>2</sup> = m<sub>0</sub>*c<sup>2</sup>
                      *(1/(1-v<sup>2</sup>/c<sup>2</sup>)<sup>1/2</sup>)<font
                        size="-1">   </font>is correct. It describes
                      the increase of mass at motion.  But your
                      equation <font size="+1"> </font>c<sup>2</sup> =
                      c<sub>0</sub><sup>2</sup> *(1/(1-v<sup>2</sup>/c<sub>0</sub><sup>2</sup>)<sup>1/2</sup>)  
                      does not have any meaning for me. And I do not
                      understand how you have deduced it. I have asked
                      you the other day what this equation means in your
                      view, but you did not answer this. Because why
                      should the speed of light change if something
                      (what??) moves at some speed v?</blockquote>
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