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<DIV><FONT color=#000080 size=2 face=Arial>Chip,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Just because a body within a frame
has inertia (as it always will!) that doesn't make it an inertial frame.
An 'inertial frame', as the term is used in this context, is one in which the
inertial mass has no bearing on the motion of the object - i.e. it is neither
being accelerated nor is it subject to gravitational effects (since
gravitational mass = inertial mass - for reasons conventional science chooses to
bypass, but which shed significant light on the whole issue if they'd just do
their homework properly!) - I'm afraid you can't simply redefine the term
'inertial mass' to suit your own view!</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT size=2><FONT color=#000080 face=Arial>You don't help your own case by
using the terms "very slightly" and "slightly" - if a person is 'slightly dead'
then they're still dead! ANY degree of curvature, no matter how "slight"
introduces forces into the equation - you can't get away from that by making
them just "slightly"! And as soon as you have forces you no longer have an
inertial frame!! NO conventional physicist would agree with your assertion
that "a slightly changing inertial frame is still an inertial frame", if that
change involves curvature of the object's path.</FONT></FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Chip, you're not just changing the
discussion (even slightly!), you're changing the definition of the terms used in
that discussion!</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>This is all rather by-the-by, since
we're both agreed that conventional SR and GR are off-beam - but we're not going
to get physics back on track by misrepresenting what it says at
present.</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial></FONT> </DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Best,</FONT></DIV>
<DIV><FONT color=#000080 size=2 face=Arial>Grahame</FONT></DIV>
<BLOCKQUOTE
style="BORDER-LEFT: #000080 2px solid; PADDING-LEFT: 5px; PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black"><B>From:</B>
<A title=chipakins@gmail.com href="mailto:chipakins@gmail.com">Chip Akins</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=general@lists.natureoflightandparticles.org
href="mailto:general@lists.natureoflightandparticles.org">'Nature of Light and
Particles - General Discussion'</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Friday, September 01, 2017 12:29
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [General] [NEW] SRT twin
Paradox</DIV>
<DIV><BR></DIV>
<DIV class=WordSection1>
<P class=MsoNormal>Hi Grahame<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>But there is a point we need to consider. A body in
motion is in an inertial frame, whether the motion is linear or is very
slightly curved depends on whether there is a transverse acceleration. The
presence of a very slight transverse acceleration does not cancel the inertia
of the body, or erase the existence of an “inertial frame” but it does
slightly alter that frame with time.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>So a slightly changing inertial frame is still an inertial
frame, but in order to fully evaluate the small effect of curvature, in such a
case, we have to use a more complete formulation of relativity.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>I understand this very well. I also understand that
when one changes the discussion to avoid the issue at hand, that I am probably
wasting my time.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>Chip<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<DIV><FONT color=#000080 size=2
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