[General] To Infinity and Beyond: zero phase index?

Tue Oct 20 22:05:07 PDT 2015

Dear David,

Blue
________________________________
From: General [general-bounces+john.williamson=glasgow.ac.uk at lists.natureoflightandparticles.org] on behalf of davidmathes8 at yahoo.com [davidmathes8 at yahoo.com]
Sent: Tuesday, October 20, 2015 6:50 AM
To: Nature of Light and Particles - General Discussion
Subject: Re: [General] To Infinity and Beyond: zero phase index?
Rich, Martin et al,

Why is a curving photon charged?

It isn't. we had a whole thread on this! Only a complete (double - not single) loop exhibits charge.

Shouldn't there be a radiation emission of some sort : ionizing or non-ionizing.

No. No radiation if charge is not accelerated. There is, therefore, no charge going round and round. Charge is a result of this (the going round and roundness - double looped). It is a place where radiations can be caught and weighed. Where radiation may be absorbed into rest massive system. Think about it: irrespective of my model or not, this is true.

Ionizing radiation is typically particles: alpha, beta, gamma and oddly enough, UV and Xray.

Ionising just means it has got enough energy to make ions. More than about an eV then.

Non-iozizing is  usually EM: DC to light and beyond, gamma, blackbody, thermal except for UV and Xray.

Not gamma. Light becomes "ionising" when it has enough energy to form ions. In this sense blue light is ionisisng and so is green. Otherwise no "greens". Convention (and convention only) draws the line at about UV.

And why is UV and Xray ionizing, while the rest of the EM spectrum not ionizing?

Ionising just means it has got enough energy to make ions. More than about an eV then.

Cosmic radiation is another matter. (bad pun)

true!

Actually, I was thinking of braking radiation and cyclotron radiation (in every 720 zbw model).

In the electron models, is there any sign of Cherenkov or Askaryan radiation? I haven't seen any so far.

Of course not. There are no accelerated charges.

Another odd observation is bremstrallung? Why doesn't the photonic electron experiencing bremstrallung?

It does : if it is decelerated quickly. It has the elementary charge.

If it does, where does it go? Is it converted?

No radiation from non-accelerated charge.

Most importantly, why isn't there synchrotron radiation? Does this mean the photon is uncharge? Or is the photonic electron an example of a non-charged particle on a curve path producing radiation?

Same reason there is no radiation from an electron in an atom. This is, often, wrongly ascribed to "quantum" effects, but it really because the electron is really stationary. Quantum mechanically stationary. Also really stationary.

In turn, this makes me wonder how the photon responds below Planck dimensions to Abraham-Lorentz force? For both quantum and relativistic solution, see Abraham–Lorentz–Dirac–Langevin equation.

Real photons are nowhere near the Plank dimension. Mu.

I do apologize for asking questions instead of not providing a robust informative discussion.

So you should! (but do not stop!).

Best,

David

regards, John W.

________________________________
From: General [general-bounces+john.williamson=glasgow.ac.uk at lists.natureoflightandparticles.org] on behalf of davidmathes8 at yahoo.com [davidmathes8 at yahoo.com]
Sent: Tuesday, October 20, 2015 6:50 AM
To: Nature of Light and Particles - General Discussion
Subject: Re: [General] To Infinity and Beyond: zero phase index?

Rich, Martin et al,